Quadratic Equation
#include<stdio.h>#include<stdlib.h>#include<math.h>void main(){float a,b,c,x1,x2,rp,ip,disc;printf("enter the co-efficients\n");scanf("%f%f%f",&a,&b,&c);if((a*b*c)==0){printf("a cannot be zero");exit(0);}disc=b*b-4*a*c;if(disc==0){printf("the roots are equal\n");x1=x2=-b/(2*a);printf("x1=%f\n x2=%f\n",x1,x2);}else if(disc>0){x1=(-b+sqrt(disc))/(2*a);x2=(-b-sqrt(disc))/(2*a);printf("the roots are real and distinct\n");printf("x1=%f\n x2=%f\n",x1,x2);}else{rp=-b/(2*a);ip=sqrt(fabs(disc))/(2*a);printf("the roots are Complex\n");printf("first root=%f+i%f\n",rp,ip);printf("second root=%f-i%f\n",rp,ip);}}
Quadratic Equation
Start
Read the co-efficient as a, b, c
if a is equal to 0 display error
else compute disc=(b*b)-(4*a*c) and r=sqrt(fabs(disc)))
if disc is equal to 0 then
compute x1=x2= -b/(a*2.0)) and display x1,x2
else If discriminant is greater than 0 then
compute (x1=(-b+r)/(a*2.0)), x2= (-b-r)/(a*2.0)) and display x1,x2
else If discriminant is lesser than zero,
display roots are complex
compute x1=(-b)/(a*2.0)+ir/(a*2.0) and x2= (-b)/(a*2.0)-ir/(a*2.0) and display x1,x2
Stop
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