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Quadratic Equation77

Quadratic Equation
#include<stdio.h>
#include<stdlib.h>
#include<math.h>
void main()
{
 float a,b,c,x1,x2,rp,ip,disc;
 printf("enter the co-efficients\n");
 scanf("%f%f%f",&a,&b,&c);
 if((a*b*c)==0)
 {
 printf("a cannot be zero");
 exit(0);
 }
 disc=b*b-4*a*c;
 if(disc==0)
{
 printf("the roots are equal\n");
x1=x2=-b/(2*a);
 printf("x1=%f\n x2=%f\n",x1,x2);
}
 else if(disc>0)
{
 x1=(-b+sqrt(disc))/(2*a);
 x2=(-b-sqrt(disc))/(2*a);
 printf("the roots are real and distinct\n");
 printf("x1=%f\n x2=%f\n",x1,x2);
}
else 
{
 rp=-b/(2*a);
 ip=sqrt(fabs(disc))/(2*a);
 printf("the roots are Complex\n");
 printf("first root=%f+i%f\n",rp,ip);
 printf("second root=%f-i%f\n",rp,ip);
}
}
Quadratic Equation
Start 

Read the co-efficient as a, b, c

if a is equal to 0 display error

else compute disc=(b*b)-(4*a*c) and r=sqrt(fabs(disc)))

if disc is equal to 0 then

compute x1=x2= -b/(a*2.0)) and display x1,x2

else If discriminant is greater than 0 then

compute (x1=(-b+r)/(a*2.0)), x2= (-b-r)/(a*2.0)) and display x1,x2

else If discriminant is lesser than zero,

display roots are complex

compute x1=(-b)/(a*2.0)+ir/(a*2.0) and x2= (-b)/(a*2.0)-ir/(a*2.0) and display x1,x2

Stop

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